機(jī)械專業(yè)外文翻譯--伺服系統(tǒng)

1、<p>　　畢業(yè)設(shè)計(jì)(論文)外文資料翻譯</p><p>　　系　　部： 機(jī)械系 </p><p>　　專 業(yè)： 機(jī)械工程及自動(dòng)化 </p><p>　　姓 名： </p

2、><p>　　學(xué) 號(hào)： </p><p>　　外文出處： 《Servo Systems》 </p><p>　　附 件： 1.外文資料翻譯譯文；2.外文原文。 </p><p>　　注：請(qǐng)將該封面與附件裝訂成冊(cè)。</p><p>

3、;　　附件1：外文資料翻譯譯文</p><p><b>　　伺服系統(tǒng)</b></p><p>　　由輸入軸隨意運(yùn)動(dòng)引起輸出軸運(yùn)動(dòng)的一種形式是同步發(fā)送接收系統(tǒng)。另一種形式是伺服機(jī)構(gòu)或伺服系統(tǒng)同步系統(tǒng)可在相當(dāng)大的距離內(nèi)在兩個(gè)分開(kāi)的軸之間工作，但不提供力矩放大—傳送到負(fù)載的力矩不能超過(guò)輸入力矩。由于這個(gè)原因，并且在傳送大力矩時(shí)，偏差角增大，同步系統(tǒng)只能用丁轉(zhuǎn)動(dòng)刻度盤和指針，

4、移動(dòng)控制活門和驅(qū)動(dòng)其他小力矩負(fù)載。另一方面，伺服系統(tǒng)可提供要求移動(dòng)大負(fù)載的大力矩，只需給輸入軸加上很小的力矩。遙控運(yùn)行不是伺服系統(tǒng)的固有特性，但可以通過(guò)數(shù)據(jù)傳送裝置實(shí)現(xiàn)，通常同步器作為系統(tǒng)的一部分。</p><p>　　一、伺服系統(tǒng)的基本要求</p><p>　　伺服系統(tǒng)是一種具有響應(yīng)和執(zhí)行指令的裝置，伺服系統(tǒng)必須能夠滿足五項(xiàng)基本要求，它們是：</p><p>　　

5、a.伺服系統(tǒng)要能夠接收規(guī)定期望結(jié)果的指令。</p><p>　　b．伺服系統(tǒng)要能夠估計(jì)存在條件。</p><p>　　c．伺服系統(tǒng)要能夠把存在條件與期望結(jié)果相比較得出差值或偏差信號(hào)。</p><p>　　d．伺服系統(tǒng)要能夠依據(jù)偏差信號(hào)，發(fā)出校正指令，正確地改變存在條件到期望結(jié)果。</p><p>　　e．伺服系統(tǒng)要有執(zhí)行校正指令的方法。<

6、;/p><p>　　為使伺服系統(tǒng)滿足五項(xiàng)基本要求，它必須具有一個(gè)偏差檢測(cè)元件和一個(gè)操縱負(fù)載位移馬達(dá)的控制器。</p><p><b>　　二、伺服系統(tǒng)部件</b></p><p>　　伺服系統(tǒng)包括偏差指示器和按照?qǐng)D1方式連接輸入和輸出軸的控制器。伺服系統(tǒng)的目標(biāo)是驅(qū)功輸出軸通過(guò)保持偏差角（輸出軸離輸入軸的角位移偏差）盡可能接近于零而重復(fù)輸入軸運(yùn)動(dòng)。偏

7、差指示器確定了偏差角的幅值和方向。在偏差指示器信號(hào)控制下，控制器在減小偏差的方向上給輸出軸施加力矩。伺服系統(tǒng)是個(gè)閉環(huán)或稱作反饋系統(tǒng)，因?yàn)榧拥娇刂破鞯男盘?hào)引起輸出軸轉(zhuǎn)動(dòng)，改變了偏差角，這樣又改變了加到控制器的信號(hào)。</p><p><b>　　圖1</b></p><p>　　偏差指示器和控制器可以采用很多種形式?？刂破鞅仨毢兴欧R達(dá)或一些產(chǎn)生輸出為矩的裝量。伺服系統(tǒng)

8、可按照所用伺服馬達(dá)的類型劃分為電動(dòng)式、液壓式、氣動(dòng)式或機(jī)械式。本文只討論電動(dòng)伺服系統(tǒng)。電動(dòng)伺服系統(tǒng)使用多種電動(dòng)馬達(dá)。除了伺服馬達(dá)外，控制器一般還包括功率放大器，能使來(lái)自偏差指示器的弱信號(hào)轉(zhuǎn)換為較大功率供給馬達(dá)。這種功率放大器通常稱作伺服放大器。偏差指示器最常見(jiàn)的是同步裝量。電動(dòng)伺服系統(tǒng)中，同步發(fā)電機(jī)和控制變換器機(jī)械聯(lián)接到輸入和輸出軸上，控制變換器即偏差指示器，其轉(zhuǎn)子電壓用作控制器的輸入信號(hào)。</p><p>&l

9、t;b>　　圖2</b></p><p>　　大部分航空電子應(yīng)用中的伺服系統(tǒng)是帶控制變換器偏差指示器的電動(dòng)伺服系統(tǒng)。這種伺服系統(tǒng)的框圖如圖2所示。若這個(gè)系統(tǒng)用直流馬達(dá)，圖中放大器必須具有將同步系統(tǒng)的交流電壓整流，同時(shí)進(jìn)行功率放大的功能，若使用交流馬達(dá)，則需要交流放大器圖2所示的系統(tǒng)中，輸入軸與輸出軸之間的偏差角，確定了由控制變換器產(chǎn)生并送到伺服放大器的偏差電壓的相位和幅值。偏差信號(hào)依次控制由伺服

10、馬達(dá)加到輸出軸上力矩的方向和幅值。電動(dòng)伺服系統(tǒng)使用很多類型的伺服馬達(dá)，而在航空電子應(yīng)用中，兩相感應(yīng)電機(jī)是應(yīng)用最廣的。因而本文只討論兩相感應(yīng)伺服馬達(dá)。</p><p>　　三、平衡電位計(jì)型偏差指示器</p><p>　　伺服系統(tǒng)中作偏差指示器的另一種裝置是平衡電位計(jì)（見(jiàn)圖3）本系統(tǒng)中有兩個(gè)電位計(jì)用在電橋中，一個(gè)電位計(jì)用于指令控制，另一個(gè)電位計(jì)機(jī)械藕合在伺服機(jī)械的輸出軸上。兩個(gè)裝置的差值將產(chǎn)生

11、偏差信號(hào)。依次引起伺服放大器或控制器轉(zhuǎn)動(dòng)輸出軸，直到電橋平衡為止。平衡電位計(jì)產(chǎn)生的偏差信號(hào)與控制變換器產(chǎn)生的偏差電壓完全是用于同樣方式。</p><p><b>　　圖3</b></p><p>　　CT（控制變換器）的指令一般來(lái)自離CT一段距離的同步發(fā)送器轉(zhuǎn)軸的運(yùn)動(dòng)，而平衡電位計(jì)轉(zhuǎn)軸指令則可加到一個(gè)電位計(jì)滑動(dòng)觸點(diǎn)的轉(zhuǎn)子上。這種系統(tǒng)的實(shí)例正如ARN-21塔康收發(fā)機(jī)的頻

12、道選擇器。平衡電位計(jì)的輸入部分位于頻道選擇器的控制端，電位計(jì)的另一部分位于收發(fā)器組件。電位計(jì)的滑動(dòng)觸點(diǎn)機(jī)械聯(lián)接到晶體狀六角轉(zhuǎn)塔上。</p><p><b>　　四、兩相感應(yīng)電動(dòng)機(jī)</b></p><p>　　經(jīng)常用于驅(qū)動(dòng)伺服機(jī)構(gòu)輸出軸的各類交流馬達(dá)中，最重要的是兩相感應(yīng)電動(dòng)機(jī)。這種電機(jī)在小容量伺服系統(tǒng)中有著廣泛的應(yīng)用，例如用于機(jī)載塔康的距離和方位指示器驅(qū)動(dòng)系統(tǒng)和用于驅(qū)

13、動(dòng)雷達(dá)平面位量指示器的偏轉(zhuǎn)線圈，還用于大多數(shù)航空電于設(shè)備上。為了了解采用感應(yīng)電動(dòng)機(jī)的伺服機(jī)構(gòu)，首先要知道這些電機(jī)的特性。</p><p><b>　　圖4</b></p><p>　　圖4給出了表示雙極、雙相感應(yīng)電動(dòng)機(jī)的轉(zhuǎn)于、剖面和電路圖。定于和轉(zhuǎn)子都是由薄鋼片疊加構(gòu)成的。定子有兩個(gè)相同的線圈：A線圈和B線圈。如此排列可使兩個(gè)線圈的磁場(chǎng)相互垂直轉(zhuǎn)子可采用線繞式短路繞組

14、或鼠籠式繞組。鼠籠繞組由轉(zhuǎn)于槽內(nèi)的導(dǎo)電條組成。這些導(dǎo)電條由轉(zhuǎn)子兩端的導(dǎo)電環(huán)短接。定子線圈通常供給幅值相等、相位相差90度的交流電，這種交流電可直接從兩相電源系統(tǒng)得到，或從單相電源利用移相電路的方式獲得如圖4 (d)所示。正如圖4 (e）的相量圖所示，B線圈電流IB因線圈的感抗而滯后于外加電壓E.A線圈電流IA因電容C的容抗大于A線圈的感抗而使電流超前于外加電壓E。適當(dāng)選擇電容值的大小，可改變IA相對(duì)E的相位，使lA和IB的相位差接近90

15、度。由于電流流過(guò)兩個(gè)線圈，通過(guò)轉(zhuǎn)子鐵芯的總磁通的幅值是常量，并由定子電流的頻率確定磁場(chǎng)沿電動(dòng)機(jī)軸轉(zhuǎn)動(dòng)的速度。圖5表明了旋轉(zhuǎn)磁場(chǎng)是如何產(chǎn)生的。圖中標(biāo)明了在電流的一個(gè)周期內(nèi)各段區(qū)間磁通的方向。圖中頂行描述了一個(gè)電流周期內(nèi)每隔90度時(shí)，定子合成磁場(chǎng)的狀態(tài)。</p><p><b>　　圖5</b></p><p>　　圖中所示的任何時(shí)刻的瞬時(shí)磁通，是流過(guò)兩個(gè)線圈電流產(chǎn)生的合

16、成磁通。相位角為零度時(shí)僅A線圈有電流，磁通方向沿A線圈軸線內(nèi)上。90度時(shí)，僅B線圈有電流，磁通方向向右。18度時(shí)，由于A線圈電流在負(fù)值方向上，所以磁通方向向下。頂行圖示說(shuō)明了供電電流每個(gè)周期內(nèi)，磁通旋轉(zhuǎn)一周的變化。圖5中第二行給出了兩個(gè)線圈都有電流時(shí)，相位角為中間值的磁通狀態(tài)。由于定子線圈的每匝都分布在槽內(nèi)，這種方式使氣隙磁通密度隨轉(zhuǎn)子的角度呈正弦規(guī)律變化，磁通在整個(gè)旋轉(zhuǎn)過(guò)程中保持恒定幅值。例如。在45度相位角，流過(guò)A線圈的電流幅值是最

17、大值的0.707倍．這個(gè)電流產(chǎn)生向上的磁通也是最大值的0.707倍。B線圈也流過(guò)幅值為最大值0.707倍的電流，產(chǎn)生最大值的0.707倍的向右的磁通。兩個(gè)成直角的磁通線圈，其合成相量轉(zhuǎn)到45度方向，幅值等于每個(gè)單個(gè)線圈的最大幅值。</p><p>　　旋轉(zhuǎn)磁通的速度叫做同步轉(zhuǎn)速，它由線圈電流的頻率決定。對(duì)于工作在400周／秒電源的雙極電動(dòng)機(jī)來(lái)說(shuō)，其同步轉(zhuǎn)速為2400轉(zhuǎn)／分。</p><p>

18、;　　兩相感應(yīng)電機(jī)中，若把任何一個(gè)定子線圈的接線端子互換，則旋轉(zhuǎn)磁通的方向?qū)⒎聪?。換句話說(shuō)，每個(gè)定子電流移相18度時(shí)，將使電動(dòng)機(jī)反轉(zhuǎn)。當(dāng)A線圈電流IA極性反向時(shí)，磁通的旋轉(zhuǎn)方向也由順時(shí)針變?yōu)榉磿r(shí)針。</p><p>　　旋轉(zhuǎn)磁通穿過(guò)轉(zhuǎn)子導(dǎo)體。在轉(zhuǎn)子導(dǎo)體中產(chǎn)生電勢(shì)，因此有電流流過(guò)轉(zhuǎn)子短路繞組，圖6表示磁通旋轉(zhuǎn)的某一瞬間，轉(zhuǎn)子電流的方向可用圓點(diǎn)和叉號(hào)表示。（圖中假定轉(zhuǎn)子轉(zhuǎn)速近似等于同步轉(zhuǎn)速，且轉(zhuǎn)子電流與轉(zhuǎn)子感應(yīng)電勢(shì)同

19、相）字母N和S代表定子旋轉(zhuǎn)磁場(chǎng)的北極和南極。N'和S'代表轉(zhuǎn)子電流產(chǎn)生的轉(zhuǎn)子磁場(chǎng)北極和南級(jí)。因此轉(zhuǎn)子成為一個(gè)磁體，試圖朝定子磁場(chǎng)方向調(diào)節(jié)自己，由此產(chǎn)生轉(zhuǎn)矩，方向是使轉(zhuǎn)子沿定子旋轉(zhuǎn)磁場(chǎng)方向轉(zhuǎn)動(dòng)。</p><p>　　附件2：外文原文（復(fù)印件）</p><p>　　Servo Systems</p><p>　　One means of causing

20、an output shaft to follow the arbitrary motion of an input shaft is the synchro transmitter-receiver system. Another means is the servomechanism or servo system. Synchro systems can operate between shafts separated by a

21、 considerable distance but cannot supply torque amplification-the torque delivered to the load can never exceed the input torque. For this reason, and because the error angle increases when large torques are transmitted

22、, synchro systems are employed only to </p><p>　　1. BASIC REQUIREMENTS OF SERVOS</p><p>　　A servo system is a device that has the ability to respond to and carry out an order. A servo system mu

23、st be able to fulfill five basic requirements. They are:</p><p>　　a. A servo must be able to accept an order which defines the result that is desired.</p><p>　　b. A servo must be able to evaluat

24、e the existing conditions.</p><p>　　c. A servo must be able to compare the desired result with the existing conditions, obtaining a difference, or error, signal.</p><p>　　d. A servo must be abl

25、e to issue a correcting order, based on the error signal, which will properly change the existing conditions to the desired result.</p><p>　　e.A servo must have the means of carrying out the correcting or

26、der.</p><p>　　In order for a servo system to meet the five basic requirements, it must possess an error detecting device and a controller that operates the load positioning motor.</p><p>　　2. C

27、OMPONENTS OF SERVO SYSTEMS</p><p>　　A servo system comprises an error indicator and a controller connected to the input and output shafts in the manner shown in Fig. 1. The object of the servo system is to

28、 cause the output shaft to repeat the motion of the input shaft by maintaining the error angle (deviation in angular position of output shaft from that of input shaft) as near to zero as possible. The error indicator det

29、ermines the magnitude and direction of the error angle. Under control of the signal from the error indicator</p><p>　　Figure 1 Basic Servo System.</p><p>　　The error indicator and controll

30、er may take a wide variety of forms. The controller must include a servo motor or some device for developing the output torque. Servos are classified as electrical, hydraulic, pneumatic, or mechanical in accordance wit

31、h the type of servo motor used. Only electrical servo systems will be discussed in this course. Electrical servos use electric motors of some sort. The controller often contains, in addition to the servo motor, a power

32、 amplifier to enable the we</p><p>　　The most used servo in avionics applications is the electrical servo with control transformer error indicator. A block diagram of this servo system is drawn is Fig. 2.

33、If a dc motor is used in this system, the amplifier in the figure must include a means of rectifying the alternating voltage from the synchro together with a means of increasing the power level. If an ac motor is used, a

34、n ac amplifier is required. In the system shown in Fig. 2 the error angle between the input and output shafts</p><p>　　Figure 2 Block Diagram of an Electrical Servo Using a Control Transformer as an Error

35、Detector. </p><p>　　3- BALANCED POTENTIOMETER ERROR INDI CATOR</p><p>　　Another type device used as an error detector in servo systems is the Balanced Potentiometer (see Fig. 3). In this</p&g

36、t;<p>　　Figure 3 Typical Balanced potentiometer System.</p><p>　　System, two potentiometers are used in a bridge circuit, where one potentiometer is a command control and the other potentiometer i

37、s mechanically coupled to the output shaft of the servomechanism. A difference between the two settings results in the production of an error signal which, in turn, will cause the servo amplifier or controller to rotate

38、 the output shaft until the bridge is balanced. The error signal produced by the balanced potentiometers is used in exactly the same way as that err</p><p>　　With the CT the order usually comes from a moveme

39、nt of a synchro transmitter shaft at some distance from the CT; but in the balanced potentiometer system, the order shaft may be attached to the rotor of the sliding contact of one potentiometer. An example of such a sys

40、tem is the channel selector in the ARN-21 TACAN transceiver. The input portion of the balanced potentiometer is located in the channel selector control head. The other part of the potentiometer is located in the transce

41、iver unit. </p><p>　　4. TWO-PHASE INDUCTION MOTOR</p><p>　　The most important of the several types of ac motors used to drive the output shafts of servomechanisms is the two-phase induction moto

42、r. This motor has wide applications in low powered servo systems such as those used in the airborne taken range and azimuth indicator drive systems and in driving the deflection yokes on the radar PPI indicators, as we

43、ll as most avionics applications. To understand servomechanisms employing induction motors it is first necessary to know the characteristics of </p><p>　　Figure 4 Two-Pole Two-Phase Induction Motor.<

44、/p><p>　　At any instant of time the flux shown in the diagrams is the resultant flux produced by currents flowing in both coils. When the phase angle is 0º, only coil A carries current, and the flux is di

45、rected upward along the axis of coil A. At 90º, only coil B carries current, and the flux is directed to the right. At 180º, the flux is directed downward because coil A carries current in the negative directio

46、n. The patterns in the top row show that the flux rotates one revolution for each cycle of the</p><p>　　Figure 5 Rotating Field in Two-Phase Induction Motor</p><p>　　Figure 6 Relation of Rotatin

47、g Flux to Rotor Currents and Torque in a Two-Phase Induction Motor</p><p>　　The speed at which the flux rotates is called the synchronous speed and depends upon the frequency of the coil currents. For a two

48、-pole motor operated from 40U cps power, the synchronous speed is 24.000 rpm.</p><p>　　Trip direction of rotation of the flux in a two-phase induction motor is reversed if the terminals of either stator co

49、il are interchanged. In other words, a 180º phase shift in either stator current will reverse the direction of the rotation of the motor. With the current Ia reversed in polarity it can be seen that the direction

50、of rotation of the magnetic flux is counterclockwise rather than clockwise as before.</p><p>　　Rotation of the magnetic flux past the conductors of the rotor induces voltages in these conductors, and current

51、s therefore flow in the short-circuited rotor winding. The direction of rotor currents are indicated by dots and crosses in Fig. 6 for a particular instant during the rotation of the flux. (In the figure, rotor currents