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1、See discussions, stats, and author profiles for this publication at: https://www.researchgate.net/publication/3780423An AC converter with a small DC link capacitorfor a 15 kW permanent magnet synchronousintegral motorCON
2、FERENCE PAPER · OCTOBER 1998DOI: 10.1049/cp:19980597 · Source: IEEE XploreCITATIONS14READS7312 AUTHORS, INCLUDING:H.-P. NeeKTH Royal Institute of Technology177 PUBLICATIONS 2,656 CITATIONS SEE PROFILEAvaila
3、ble from: H.-P. NeeRetrieved on: 27 January 2016Royal Institute of Technologyconv10uFsyntestCreated: Last Modified: Printed On:June 26, 1996 (es95-45) March 17, 1998 (karsten) March 17, 1998 (karsten)SS 1GG DD10D D DD D
4、D111100E-6100E-6100E-60.0010.0010.001ABCGGDD G DGD0.00240.00240.00240.250.250.25ABCPhaseFreqMag Sin72 -2400.9ABCompar- atorABCompar- ator100E-9 100E-9ABCompar- atorABCompar- atorPhaseFreqMag Sin-120 720.9ABCompar- atorAB
5、Compar- ator PhaseFreqMag Sin720.90Figure 1: Schematic diagram of the considered sys- tem400450500550600650700V0.16 0.165 0.17 0.175 0.18sFigure 2: Typical simulated instantaneous value of the DC link voltage. fSW = 6 kH
6、z, fout = 72 HzasUl?l = m√3 √2Udc2 = 0.612 m Udc . (2)A typical simulated instantaneous value of the DC link voltage is shown in Figure 2. The ripple con- sists of two components – one produced by the recti- fier and one
7、 produced by the inverter which will be discussed in the next Section. If the size of the ca- pacitor is changed, the ripple in the DC link voltage will be changed. The maximum peak-to-peak volt- age has a substantial de
8、crease between the capacitor sizes 1 µF and 10 µF and remains almost constant for larger capacitor values, which can be seen in Fig- ure 5. Using a capacitor of 10µF leads to a peak to peak voltage ripple
9、of ?Udc = 290 V. The inverter output current is very close to the si- nusoidal waveform, even though no closed loop con- trol was used. A typical waveform of this current in one phase is shown is Figure 3. It consists ma
10、inly of the desired fundamental frequency (fout = 72 Hz), superimposed with small ripples caused by the high frequency inverter pulses.-50-2502550A0.16 0.167 0.174 0.181 0.188 0.195sFigure 3: Inverter output currentANALY
11、TICAL EVALUATION OF THE DC LINK VOLTAGEThe basic idea of this analysis originated from ob- servation of the instantaneous DC link voltage (Fig- ure 2) obtained from the simulations [4]. The voltage is a composition of th
12、e rectifier output voltage hav- ing a dominant frequency of 6 · 50 = 300 Hz, super- imposed with the ripple caused by the pulse width modulation of the inverter. The peak-to-peak ripple in the DC link voltage caused
13、 by the rectifier can be calculated from,?UR = √2 U ??32 U (3)assuming that U is the line-to-line rectifier input voltage [5]. To get an analytical expression of the DC link volt- age ripple caused by the inverter, the i
14、nstantaneous power flowing into the DC link was compared with the instantaneous power flowing out of it during one switching interval. The phase output voltages of the inverter consist only of two distinct levels, ei- th
15、er + Udc2 or ? Udc2 , with respect to the midpoint of the DC link voltage. Ud is the mean DC link volt- age, which is assumed to be constant in this analysis. The duration of the pulse, where the phase voltage has the ne
16、gative value ? Udc2 , named tp, depends on the instantaneous value of the sinusoidal reference wave for each phase. The analytical relation between tp and the desired instantaneous value of a certain output phase voltage
17、, ui, can be written astpi = TSW2?1 ? 2uiUdc?. (4)From this point is is possible to calculate the en- ergy drawn from the capacitor for each section of one switching interval TSW . Calculating the energies Wi over the wh
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