成人高考數(shù)學(xué)試題及參考答案

1、00000000000.1.()()()=0()()bcda??一選擇題以下結(jié)論正確的是（)a若函數(shù)f(x)在點(diǎn)x處連續(xù)，則fx一定存在函數(shù)f(x)的導(dǎo)數(shù)不存在的點(diǎn)，一定不是f(x)的極值點(diǎn)若函數(shù)f(x)在點(diǎn)x處有極值，且fx存在，則必有fx若x為函數(shù)f(x)的駐點(diǎn)，則x必為f(x)的極值點(diǎn)2.函數(shù)y=f(x)在點(diǎn)x處的左導(dǎo)數(shù)fx和右導(dǎo)數(shù)fx存在且相等是f(x)在CB點(diǎn)x可導(dǎo)的()充分條01sinsin..2xxcdxxa??件b充要條

2、件c必要條件d非充分必要條件3.當(dāng)x時(shí)，下列變量與X為等價(jià)無(wú)窮小量的是()a.In(1x)b.Axsin223424.sin0()112215.()221122xyxeyyxxxAxxabcdxxxx???????????????由方程確定的隱函數(shù)則此曲線在點(diǎn)（0，0）處的切線斜率為()a1bc1dA26.()(1)()111(01)(0)(1)()222()cos2()7.()11.2sin2.sin2.sin2.2sin2228.1

3、19.()()()().(xxfxxxfxabcdfxdxxcfxAxBxCxDxyazzInxaxxyabcdxyxxfxdxFxcefedxFDeBa????????????????????設(shè)則的單調(diào)遞增區(qū)間是=()則若設(shè)則等于=()DC若則).().().()10.xxxxxcbFecceFeCdFecAB????????設(shè)與為互不相容事件，則下列等式正確是()A.p(AB)=1B.P(AB)=P(A)P(B)C.P(AB)=0D

4、.P(AB)=P(CA)P(B)22222222122210021.lim5222(2)()lim)53(2)(3)616.22.()()2xxxxxtttxxaxbxxaxbxxxaxbxxkxkkaxbxxaxbxabfxedteedtfxx???????????????????????????????????????????參考答案：解：若則當(dāng)時(shí)，與為同階無(wú)窮小量，令則（此時(shí)代入式得x即xx所以解：因?yàn)樗?2(1)323111.

5、23.431121122arctan2()2242xxeexxyxttdxtdxtdtttxx?????????????????????????解：因y得點(diǎn)M(21)所求切線方程為y1=11(x2)即11xy21=024解：1112222222225.()8.60.29.10.39.40.29.90.39.3()8.50.29.00.29.50.210.00.39.3()()9.3)(8.69.3)0.2(9.19.3)0.3(9.49

6、.3)0.2(9.99.3)0.30.22)(8.59.3)0.2(ExExExExxx????????????????????????解：由于（環(huán))D(D(222122“9.29.3)0.3(9.59.3)0.2(10.09.3)0.30.31()()1=660011260.21122001DXDXxxxxyxxyxX??????????????????????因?yàn)樗约椎纳鋼羲礁?6.令y得或，得所以函數(shù)的單調(diào)增區(qū)間為（，0）和（

7、1，），單調(diào)減區(qū)間為（0，1），函數(shù)Y的凸區(qū)間為（，），凹區(qū)間為（，），故時(shí)，函數(shù)有極大值，時(shí)，函333311lim23)222327.2sin()(1)0xzxxyxxazazXxxzaxax????????????數(shù)有極小值1，且點(diǎn)（，）為拐點(diǎn)，因（不存在，且沒(méi)有無(wú)意義的點(diǎn)，胡故函數(shù)沒(méi)有漸遠(yuǎn)線.解：等式兩邊對(duì)求導(dǎo)的e??0000028.()()()()()()()()aaaaaaafxdxfxdxfdxdfxdxfxdxfxfxdx