自由截面剛性分析

1、22:112019105Engineer:Sheet:Section_by_nodesFile:自由截面剛性分析.xlsCROSSSECTIONPROPERTIESDescribedbyNodesCodinatesSampleBoxGirderSectionUnits:mNodesCodinatesSectionPropertiesAboutCentroidalAxisParalleltoiginalAxisXYf=0.000degXd

2、im=3.30m10.0000.000A=2.39m^2Ydim=1.25m20.6000.000Xcg=0.000mSx(top)=0.631m^330.8650.870Ycg=0.748mSx(bot)=0.423m^341.6501.050Ixo=0.317m^4Sy(left)=0.664m^351.6501.250Iyo=1.096m^4Sy(right)=0.664m^361.6501.250Ixyo=0.0000m^471

3、.6501.05080.8650.870SectionPropertiesAboutPrincipalAxis90.6000.000f=0.000degSxp(top)=0.6m^3100.0000.000Ixp=0.3m^4Sxp(bot)=0.4m^311Iyp=1.1m^4Syp(left)=0.7m^312Ixyp=0.0m^4Syp(right)=0.7m^313J=1.4m^4141516171819202122232425

4、262728293031323322110112211001122322:112019105Engineer:Sheet:Tsion_PropertiesFile:自由截面剛性分析.xlsTsionalConstantsfCommonSections(Ref.Roark)Units:ftThinWallBoxK=2tt1(at)2(bt1)2(atbt1t2t12)TsionalConstantAverageStressts=T(2t(

5、at)(bt1))nearlengthofshtsidestL=T(2t1(at)(bt1))nearlengthoflongsidesNote:UseK2fconcreteboxgirdersaft15.65bft5.5tft1.333t1ft0.75tbKft^4408Tkipft1000tspsi15.64tLpsi68.08at1SolidsquareK=(2.2516)a4asquaresidedimensiont=0.601

6、8Ta3atpointofeachsideaaft10Kft^41406Tkipft1000atpsi33.4SolidrectangleK=ab3[130.21ba(1b412a4)]fabt=3Tab2[10.6095(ba)0.8865(ba)21.8023(ba)30.91(ba)4]aft6bft3.5bba0.583Kft^455Tkipft1000atpsi398.2SolidCircleK=pR42t=2TpR3Rft3

7、Kft^4127Tkipft1000tpsi163.7TSectionK=K1K2K1=ab3[130.21ba(1b412a4)]K2=cd3[130.105dc(1d4192c4)]aaft8.5bbft3cft3dft3.5cK1ft^460K2ft^427Kft^487dISectionaK=2K1K2bK1=ab3[130.21ba(1b412a4)]K2=(13)cd3dcaft8.5bft3cft3dft3.5bK1ft^