第二版數(shù)字邏輯習(xí)題答案

1、毛法堯第二版習(xí)題一1.1把下列不同進(jìn)制數(shù)寫成按權(quán)展開式:⑴(4517.239)10=4103510211017100210131029103⑵(10110.0101)2=124023122121020021122023124⑶(325.744)8=382281580781482483⑷(785.4AF)16=7162816151604161A162F1631.2完成下列二進(jìn)制表達(dá)式的運(yùn)算:1.3將下列二進(jìn)制數(shù)轉(zhuǎn)換成十進(jìn)制數(shù)、八進(jìn)制數(shù)和十

2、六進(jìn)制數(shù)：⑴(1110101)2=(165)8=(75)16=7165=(117)10⑵(0.110101)2=(0.65)8=(0.D4)16=131614162=(0.828125)10⑶(10111.01)2=(27.2)8=(17.4)16=11674161=(23.25)101.4將下列十進(jìn)制數(shù)轉(zhuǎn)換成二進(jìn)制數(shù)、八進(jìn)制數(shù)和十六進(jìn)制數(shù)精確到小數(shù)點(diǎn)后5位：⑴(29)10=(1D)16=(11101)2=(35)8⑵(0.207)10

3、=(0.34FDF)16=(0.001101)2=(0.15176)8⑶(33.333)10=(21.553F7)16=(100001.010101)2=(41.25237)8⑵0.0101100.100110[0.0101100.100110]原=1.010000；∴0.0101100.100110=0.010000。[0.0101100.100110]反=[0.010110]反[0.100110]反=0.0101101.011001

4、=1.101111∴0.0101100.100110=0.010000[0.0101100.100110]補(bǔ)=[0.010110]補(bǔ)[0.100110]補(bǔ)=0.0101101.011010=1.110000∴0.0101100.100110=0.0100001.9分別用“對(duì)9的補(bǔ)數(shù)”和“對(duì)10的補(bǔ)數(shù)”完成下列十進(jìn)制數(shù)的運(yùn)算：⑴2550123[2550123]9補(bǔ)=[2550]9補(bǔ)[123]9補(bǔ)=0255099876=02427∴2550

5、123=2427[2550123]10補(bǔ)=[2550]10補(bǔ)[123]10補(bǔ)=0255099877=02427∴2550123=2427⑵537846（將運(yùn)算結(jié)果在轉(zhuǎn)化成真值）（將運(yùn)算結(jié)果在轉(zhuǎn)化成真值）[537846]9補(bǔ)=[537]9補(bǔ)[846]9補(bǔ)=05379153=9690∴537846=309[537846]10補(bǔ)=[537]10補(bǔ)[846]10補(bǔ)=05379154=9691∴537846=3091.10將下列8421BCD碼轉(zhuǎn)