初一數(shù)學(xué)培優(yōu)競(jìng)賽專題--整式的加減

1、三鑫學(xué)校戴堂軍(18802594458)初一數(shù)學(xué)培優(yōu)競(jìng)賽專題初一數(shù)學(xué)培優(yōu)競(jìng)賽專題——整式的加減整式的加減一、同類項(xiàng)的基本概念一、同類項(xiàng)的基本概念1已知與是同類項(xiàng)，則m=________，n=__________323mxy??53nwxy?2若與是同類項(xiàng)，則=________，=_________234mxy??37223nxy?22mn?22nm?3在多項(xiàng)式（其中m，n為正整數(shù)）中兩項(xiàng)32124199334mnmnmnnmuvxyuv

2、xy?????是同類項(xiàng)，則的值為________mn?4設(shè)m和n均不為零，和是同類項(xiàng)，則233xy2235mnxy???=_____322332233395369mmnmnnmmnmnn??????二、整式的加減二、整式的加減1合并同類項(xiàng)（1）（2）22231()(2)22xxx????22(932)(52)xxxx??????（3）（4）()()()abcbcacab????????222(31)3(22)xxxx?????2求整式與

3、的差2352xx??223xx??三鑫學(xué)校戴堂軍(18802594458)6一個(gè)多項(xiàng)式減去多項(xiàng)式，馬虎同學(xué)將減號(hào)抄成了加號(hào)，運(yùn)算結(jié)果A2253xx??是，求多項(xiàng)式237xx???A7若多項(xiàng)式可化為六次二項(xiàng)式，求的值1132nnmxxx????2231nm??8已知，求代數(shù)式3322276ababab?????332232()(3)2()baababbab?????的值9當(dāng)時(shí)，代數(shù)式的值為18，求代數(shù)式的值1x??3238axbx??96